#author("2023-09-08T11:46:33+09:00","default:takataka","takataka") #author("2023-09-08T13:53:14+09:00","default:takataka","takataka") * データ分析 2023年度 ex03notebookB の問題の解答 [#xa9b83a6] &color(red){''工事中''}; //&color(red){''工事中''}; #contentsx //////////////////////////////////////// ** 和の記号に関する復習 [#v1fdd57b] *** A0a [#t5e4efc4] #mathjax{{ \begin{aligned} \sum_{n=1}^{4}x_n &= x_1 + x_2 + x_3 + x_4 \\ &= 10 + 20 + 30 + 40 = 100\\ \sum_{n=5}^{8}x_n &= x_5 + x_6 + x_7 + x_8\\ &= 50 + 60 + 70 + 80 = 260 \end{aligned} }} *** A0b [#d018bfc6] #mathjax{{ (\mbox{与式}) = x_1^2 + x_2^2 + x_3^2 = 100+400+900 = 1400 }} *** A0c [#bb7d4498] #mathjax{{ \begin{aligned} (\mbox{与式}) &= \sum_{n=1}^{4}x_n + \sum_{n=1}^{4}\pi = 100 + (\pi + \pi + \pi + \pi) = 100+4\pi \end{aligned} }} *** A0d [#tb3f3a5f] #mathjax{{ (\mbox{与式}) = 2\sum_{n=1}^{4} x_n = 2\times 100 = 200 }} *** A0e [#h386ba9e] #mathjax{{ \begin{aligned} (\mbox{与式}) = a\sum_{n=1}^{4}x_n + \sum_{n=1}^{4}b = 100a + 4b \end{aligned} }}