#author("2023-09-08T11:46:33+09:00","default:takataka","takataka")
#author("2023-09-08T13:53:14+09:00","default:takataka","takataka")
* データ分析 2023年度 ex03notebookB の問題の解答 [#xa9b83a6]

&color(red){''工事中''};
//&color(red){''工事中''};

#contentsx


////////////////////////////////////////
** 和の記号に関する復習 [#v1fdd57b]

*** A0a [#t5e4efc4]

#mathjax{{
\begin{aligned}
\sum_{n=1}^{4}x_n &= x_1 + x_2 + x_3 + x_4 \\
&= 10 + 20 + 30 + 40 = 100\\
\sum_{n=5}^{8}x_n &= x_5 + x_6 + x_7 + x_8\\
&= 50 + 60 + 70 + 80 = 260
\end{aligned}
}}

*** A0b [#d018bfc6]

#mathjax{{
(\mbox{与式}) = x_1^2 + x_2^2 + x_3^2 = 100+400+900 = 1400
}}

*** A0c [#bb7d4498]

#mathjax{{
\begin{aligned}
(\mbox{与式}) &= \sum_{n=1}^{4}x_n + \sum_{n=1}^{4}\pi = 100 + (\pi + \pi + \pi + \pi) = 100+4\pi
\end{aligned}
}}

*** A0d [#tb3f3a5f]

#mathjax{{
(\mbox{与式}) = 2\sum_{n=1}^{4} x_n = 2\times 100 = 200
}}


*** A0e [#h386ba9e]

#mathjax{{
\begin{aligned}
(\mbox{与式}) = a\sum_{n=1}^{4}x_n + \sum_{n=1}^{4}b = 100a + 4b
\end{aligned}
}}

トップ   編集 差分 履歴 添付 複製 名前変更 リロード   新規 一覧 検索 最終更新   ヘルプ   最終更新のRSS